a compound contains 24.27 percent carbon 4.07 percent of hydrogen and 71.65 percent of chlotine. Determine the empirical formula of the compound. thee Molecular mass of this compound is found to be 99g also determine the molecule formula of this compound
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Thus, the empirical formula of the compound is CH2Cl. For CH2Cl, empirical formula mass= 12+ (2×1) +35 = 49g. Molar mass/ empirical formula = 98.96g/ 49g = 2=n Therefore, Empirical formula = CH2Cl n=2 Hence, molecular formula= C2H4Cl2.
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