Chemistry, asked by jjohananil, 11 months ago

A compound contains 28% N and 72% of a metal by weight. Three atoms of metal combine with two atoms of N. Find the atomic weight of metal.

Answers

Answered by sknirwal
2

Answer:

Explanation:Three atoms of M combine with 2 atoms of N.

Equivalent weight of N=  

3 *14

(valency of N in compound = 3)

28g N combines with 72g metal.

3 *14

​ N combines =  

28

72  ×  3

14  =12

The equivalent weight of metal =12

Atomic mass of metal = equivalent weight × valency=12×2=24.

Hence, option A is correct.

Answered by 2049assassinscreed
2

Answer:

24

Explanation:

Three atoms of M combine with 2 atoms of N.

Equivalent weight of N=  

3 *14

(valency of N in compound = 3)

28g N combines with 72g metal.

3 *14

​ N combines =  

28

72  ×  3

14  =12

The equivalent weight of metal =12

Atomic mass of metal = equivalent weight × valency=12×2=24.

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