Question

A compound contains 28% N and 72%of a metal by weight. Three atoms of metal combine with two atoms of N. Find the atomic weight of metal.​

Answer 1

Answer:

Three atoms of M combine with 2 atoms of N.

Equivalent weight of N=

3

14

(valency of N in compound = 3)

28g N combines with 72g metal.

3

14

N combines =

28

72

×

3

14

=12

The equivalent weight of metal =12

Atomic mass of metal = equivalent weight × valency=12×2=24.

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Answer 2

Answer:

Three atoms of M combine with 2 atoms of N.

Equivalent weight of N= 14/3

(valency of N in compound = 3)

28g N combines with 72g metal.

$</p><p></p><p></p><p>314 N \: combines =2872×314=12</p><p></p><p>$

The equivalent weight of metal =12

Atomic mass of metal = equivalent weight × valency=12×2=24.