a compound contains 28% of Nitrogen and 72% of the metal by with three atom of the metal combined with two atom of Nitrogen find the atomic weight of the metal
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Explanation:
Three atoms of M combine with 2 atoms of N.
Equivalent weight of N= 14÷3 (valency of N in compound = 3)
28g N combines with 72g metal.
14÷3 N combines = 72÷28 × 14÷3 = 12
The equivalent weight of metal =12
Atomic mass of metal = equivalent weight × valency = 12×2=24.
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