Question

a compound contains 33 oxygen and 66 hydrogen by mole find E.F​

Answer 1

Answer:

A compound contains 40% carbon, 6.7% hydrogen, and 53.3%oxygen.

100 g of the compound will contain 40 g C, 6.7 g H and 53.3 g O.

The atomic masses of C, H and O are 12 g/mol, 1 g/mol and 16 g/mol respectively.

The number of moles of C=

12 g

40 g

=3.33 mol

The number of moles of H=

1 g

6.7 g

=6.7 mol.

The number of moles of O=

16 g

53.3 g

=3.33 mol.

The mole ratio C:H:O=3.33:6.7:3.33=1:2:1

The empirical formula of compound is CH

2

O.

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Explanation:

Answer 2

Answer:

E.F is $H_2O$

Explanation:

Here given,a compound contains 33 oxygen and 66 hydrogen.

We want to find E.F.

By one example, we can understand this concept more easily.

Let a compound contains 40% carbon, 6.7% hydrogen, and 53.3%oxygen.

100 g of the compound will contain 40g C, 6.7g H and 53.3g O.

The atomic masses of C, H and O are 12 g/mol, 1 g/mol and 16 g/mol respectively.

The number of moles of C= $\frac{40 \: g}{12 \: g} = 3.33 \: mol$

The number of moles of H= $\frac{6.7 \: g}{1 \: g} = 6.7 \: mol$

The number of moles of O= $\frac{53.3 \: g}{16 \: g}$ =3.33 mol.

The mole ratio C:H:O = 3.33:6.7:3.33 = 1:2:1

The empirical formula of compound is $CH_2O$

Here given,a compound contains 33 Oxygen and 66 Hydrogen.

The mole ratio of Oxygen and Hydrogen = O:H

$= 33:66 \\ = 1:2$

The empirical formula of compound is $OH_2$

Know more about E.F:

1) https://brainly.in/question/18975928

2) https://brainly.in/question/25092304