Question

A compound contains 34.1 % oxygen, 52.2% carbon and 13.0% hydrogen. Calculate the empirical
formula for compound.​

Answer 1

Answer:

Explanation:

percentage of oxygen=34.1%

therefore mass ratio=34.1/16=2.131

percentage of carbn=52.2%

therefore mass ratio=52.2/12=4.35

percentage of hydrogen= 13%

therefore mass ratio=13

ratio of mass ratios(XD): 2.131 : 4.35: 13=1:2:6=O:C:H

therefore empirical formula will be C2H6O

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