Question

A compound contains 38.8%C,16%H and 45.2%N the formula of the compound would be

Answer 1

Answer:

Empirical Formula:- CH4N (Methylamide)

Explanation:

Given,

Carbon = 38.8% = 38.8 g

Hydrogen = 16% = 16 g

Nitrogen = 45.2% = 45.2 g

• Now convert grams into moles :-

moles of Carbon:- 38.8/12.01 = 3.230

moles of Hydrogen:- 16/1.008= 15.873

moles of Nitrogen:- 45.2/14.006= 3.227

• Divide each of the mole values obtained above by the smallest number among them

so, here 3.227 is smallest value.

we get ratio 1 :4 :1

So,Empirical formula is CH4N