Question

a compound contains 38.8 % carbon 16% hydrogen and 45.2 % nitrogen the formula of the compound would be​

Answer 1

Answer: CH5O

Explanation:

1. Divide the percentage with atomic mass of the element

2 then divide the ratios by the smallest no obtained out of the three

Answer 2

Answer:

formula is C$H_{5}$N

Explanation:

Given data

carbon = 38.8 %

hydrogen = 16%

nitrogen = 45.2 %

to find out

formula of the compound

solution

we consider mass in g, so

we know that total mass 100% = 100 g

so we can say that

Mass of carbon is =  38.8 % /100% = 38.8 g

Mass of hydrogen = 16% / 100%  = 16 g

Mass of nitrogen =45.2% / 100% = 45.2 g

and we know

molar mass of carbon = 12 g/mole

molar mass of hydrogen = 1 g/mole

molar mass of nitrogen = 14 g/mole

so now we convert mass into moles

carbon moles = 38.8 / 12 = 3.23 moles

hydrogen moles = 16 / 1 = 16 moles

nitrogen moles = 45.2 / 14 = 3.23  moles

we see here 3.23 moles is small as compare to other so we find mole ration by divide 3.23 moles

so ratio are

carbon = 3.23 /3.23 = 1

hydrogen = 16 /3.23 = 4.95 = 5

nitrogen = 3.23 / 3.23 = 1

so are are come here

C:H:N are 1:5:1

so empirical formula is C$H_{5}$N