Question

a compound contains 4.07% H,24.27% C and 71.65%Cl.Its molecular mass is 98.96.Calculate it's empirical and molecular formula
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Answer 1

Answer:

For CH2Cl, empirical formula mass= 12+ (2×1) +35 = 49g. Molar mass/ empirical formula = 98.96g/ 49g = 2=n Therefore, Empirical formula = CH2Cl n=2 Hence, molecular formula= C2H4Cl2