Question

A compound contains 4.07%
hydrogen ,24.27% carbon,
71.65% chlorine. Its molecular
mass is 98.96%. What is its
empirical formula ? (C=12, H=1,
CI=35.5%)

a) CHCI
b) CHC13
c) CH2C1
d) CHCi3​

Answer 1

Answer:

step 1

Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical formula is

CH 2Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C 2H 4 Cl 2.

Answer 2

Answer:

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