A compound contains 4.07 hydrogen 24.27 carbon and 71.65 chlorine
Answers
Atomic numbers of 1 chlorine has 35.5 , 1 carbon has 12.13 and hydrogen has 1 based on the given question 4 hydrogen atoms, 2 carbon atoms and 2 chlorine atoms
Answer:
Hydrogen Carbon Chlorine
mass 4.07 24.27 71.65
RAM 1 12 35.5
no. of moles 4.07/1 24.27/12 71.65/35.5
4.07 2.02 2.02
divide by the 4.07/2.02 2.02/2.02 2.02
least no 2 1 1
Empirical formula therefore is H2CCl
the molecular formula is (EF)n=MF
(1+1+12+35.5)=49.5......98.96/49.5=2 n=2
(H2CCl)2=H4C2Cl2
therefore the molecular formula is C2H4Cl2 (dichloroethane)