Question

A compound contains 4.07 hydrogen 24.27 carbon and 71.65 chlorine. its molecular mass is 98.96 u. what are its empirical and molecular formulae

Answer 1

Hydrogen = 4g = 4 moles = 4 atoms
Carbon = 24.27g = 24.27/12 = 2atoms
Chlorine = 71.65g = 71.65/35.5 = 2 atoms

Empirical formula = CH2Cl

Empirical mass = 49

n = molar mass/empirical mass = 2

Molecular formula = C2H4CL2

Answer 2

empirical formula is the C2H4Cl2