Question

A compound contains 4.07

% hydrogen, 24.27% carbon and 71.65 %

chlorine by mass. Its molar mass is 98.96

g. What is its empirical formula ? Atomic

masses of hydrogen, carbon and chlorine are

1.008, 12.000 and 35.453 u, respectively​

Answer 1

Explanation:

Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical formula is

CH

2

Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C

2

H

4

Cl

2

.

BY TEJAS KULKARNI PLEASE FOLLOW AND MARK AS BRAINLIST AND FOLLOW FOR MORE ANSWERS!!