Question

A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% of chlorine. Its mola
98.96g. What are its empirical and molecular formulas?​

Answer 1

Answer:

Empirical formula CH2Cl

Molecular formula C2H4Cl2

Explanation:

Carbon, C=24.27/12=2/2=1

Hydrogen, H=4.07/1=4/2=2

Chloride, Cl=71.65/32.5=2/2=1

Empirical formula =CH2Cl

Molecular formula =C2H4Cl2