A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% of chlorine. Its molar mass is 98.96g. What are its empirical and molecular formulas?
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Answer:
Chemistry
A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96g. What are its empirical and molecular formulas?
December 27, 2019avatar
Nizam Yaswanth
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ANSWER
step 1
Divide the given percentages of atoms with their molecular masses
H---4.07/1 =4.07
C---24.27/12 =2.02
Cl--71.65/35.5=2.01
step 2
divide all values with the lowest value obtained.
H---4.07/2.01=2
C---2.02/2.01=1
Cl---2.01/2.01=1
therefore the empirical formula is
CH_2ClCH
2
Cl
WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5
Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C_2H_4Cl_2C
2
H
4
Cl
2
.
Answer:
hey!
Chemistry
A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96g. What are its empirical and molecular formulas?
December 27, 2019avatar
Nizam Yaswanth
SHARE
ANSWER
step 1
Divide the given percentages of atoms with their molecular masses
H---4.07/1 =4.07
C---24.27/12 =2.02
Cl--71.65/35.5=2.01
step 2
divide all values with the lowest value obtained.
H---4.07/2.01=2
C---2.02/2.01=1
Cl---2.01/2.01=1
therefore the empirical formula is
CH_2ClCH
2
Cl
WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5
Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C_2H_4Cl_2C 2 H4 Cl2 .
hope it will be helpful ✌️