Question

A compound contains 4.07% Hydrogen
24.27% of carbon and 71.65% of chlorine
molar mass 98.96gm
​

Answer 1

Explanation:

step 1

Divide the given percentages of  atoms with their molecular masses

H---4.07/1      =4.07

C---24.27/12  =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the lowest value obtained.

 H---4.07/2.01=2

 C---2.02/2.01=1

 Cl---2.01/2.01=1

therefore the empirical formula is

CH2Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C2H4Cl2.