Question

A compound contains 4.07 % of h and 71.65% of cl its molar mass is 98.6 gm what are its molecular formula and empirical formula

Answer 1

                    Hydrogen          Carbon             Chlorine
       mass      4.07                 24.27                 71.65
       RAM         1                      12                     35.5
no. of moles  4.07/1               24.27/12            71.65/35.5
                      4.07                    2.02                2.02
divide by the   4.07/2.02          2.02/2.02         2.02
 least no            2                           1                 1

Empirical formula therefore is H2CCl

the molecular formula is (EF)n=MF


(1+1+12+35.5)=49.5......98.96/49.5=2  n=2

(H2CCl)2=H4C2Cl2

therefore the molecular formula is C2H4Cl2 (dichloroethane)

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