Question

A compound contains 4.67% of hydrogen 24.27% of carbon 71.65%of chlorine. the molecular mass is 98.96 what empirical
and molecular formule?​

Answer 1

Explanation:

Thus, the empirical formula of the compound is CH2Cl. For CH2Cl, empirical formula mass= 12+ (2×1) +35 = 49g. Molar mass/ empirical formula = 98.96g/ 49g = 2=n Therefore, Empirical formula = CH2Cl n=2 Hence, molecular formula= C2H4Cl2.

Answer 2

Explanation:

Thus, the empirical formula of the compound is CH2Cl. For CH2Cl, empirical formula mass= 12+ (2×1) +35 = 49g. Molar mass/ empirical formula = 98.96g/ 49g = 2=n Therefore, Empirical formula = CH2Cl n=2 Hence, molecular formula= C2H4Cl2.