Question

a compound contains 4.o7% hydragen ,24.27% carbon and the rest chlorine its molecular mass is 99 find empirical and molecular formula​

Answer 1

Answer:

Moles of hydrogen= 4.07g/ 1g = 4.0 Moles of carbon= 24.27g/ 12g = 2.0 Moles of chlorine= 71.65g/ 35g= 2.0 Since 2.0 is the smallest value, so by dividing each of the mole values obtained by this smallest value we will get a ratio of 2:1:1 for H:C:Cl. Thus, the empirical formula of the compound is CH2Cl

Explanation:

Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01divide all values with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical formula is

CH2CL

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96

Hope it helps you

have a great day ahead

Answer 2

Answer:

If you will mark be as a brainlist then I will tell you the answer