Question

A compound contains 42.39% K, 15.2% Fe, 19.56% C and 22.8% N. The molecular mass of the cilompound is 368u.Find the molecular formula of the compound

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student-name Vallabh Vp asked in Chemistry

8 A compound contains 42.39% K, 15.21% Fe, 19.56% C

and 22.83% N. Molecular mass of compound is 368 U

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student-name Girish Sharma answered this

259 helpful votes in Chemistry, Class XII-Science

S.No. Element Percentage Atomic mass No. of moles = Percent/Atomic mass Simplest molar ratio Simplest whole no. molar ratio

1 K 42.39 39.09 42.39/ 39.09 =1.084 1.084/1.084 = 1 4

2 Fe 15.21 56 15.21/ 56 = 0.27 0.27/1.084 = 0.24 1

3 C 19.56 12 19.56 / 12 = 1.63 1.63/1.084 = 1.50 6

4 N 22.83 14 22.83 / 14 = 1.63 1.63/1.084 = 1.503 6

Empirical formula = K​4[Fe(CN)6]

Empirical formula mass = 4×39.09 + 1×56 + 6×12 + 6×14 = 368.36 u

n = Molecular massEmpirical formula mass = 368368.36 = 0.99 = 1

So , the molecular formula is ​K​4[Fe(CN)6]

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