A compound contains 49.3% carbon, 9.59% hydrogen and 19.18% nitrogen find out its molecular formula if it's molecular mass is 146
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Explanation:
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Divide all the percentages with atomic mass,
Carbon 49.2 12 49.2 =4.1 3
Hydrogen 9.68 1 9.68 =9.68 9
Nitrogen 19.9 14 19.9 =1.4 1
Oxygen 21.22 16 21.22 =1.3 1
Empirical formula will be C 3 H 9
NO
(Emperical formula wt) n =146 (75) n =146 or n=2,
Molecular will be C 6 H 18 N 2 O 2
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Explanation:
the oxidation process involves
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