A compound contains 5.07% hydrogen, 26.27% carbon and 72.65% chlorine. Its molar mass is 98.96. What are its empirical formula amd molecular formulas ?
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Explanation:
step 1
Divide the given percentages of atoms with their molecular masses
H---4.07/1 =4.07 C---24.27/12 =2.02
CI--71.65/35.5=2.01
step 2
divide all values with the lowest value obtained.
H---4.07/2.01=2
C---2.02/2.01=1
CI---2.01/2.01=1
therefore the empirical formula is
CH₂Cl
WEIGHT OF EMPIRICAL
FORMULA=12+2+35.5=49.5
Given molecular weight =98.96 which is double of empirical weight.therefore molecular formula is C₂H4Cl2.
Answered by
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Answer:
98.96 is ur answer
dear hope its help u
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