Question

A compound contains 52.2% C and 13% hydrogen and remaining percentage oxygen. The empirical
formula of the compound is
1) CHO
2) C,H,O
3) C,H,O2
4) CHO​

Answer 1

Explanation:

Pls see the attachment

Hope this helps

Answer 2

Answer:

Answer is C2H6O

Explanation:

method to find emprical formula is.

percentage.

C=52.2%

H=13%

O=100-52.2-13=34.8%

Mole ratio.

H=13/1=13

O=34.8/16=2

C=52.2/12=4

simple ratio

divide each by least value of mole ratio

H=13/2=6

O=2/2=1

C=4/2=2

Hence;

Emprical formula is;

C2H6O