a compound contains 83% C and 17% H. what is the empirical formula of compound ?
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Explanation:
Assume you have a 100 g sample. it would contain 17g H and 83 g C.
The atomic mass of H is 1 g/mol. The sample has 17 mol H.
The atomic mass of C is 12 g/mol. The sample has 6.9 mol C.
The mol ratio (C:H) is 6.9:17, which corresponds to 1:2.5, which corresponds to 4:10.
The empirical formula of the compound is C4H10.
You should be able to fill in the steps (that I haven’t shown) that were needed to reach this answer. You should also be able to confirm that the percent composition of butane is 83% C and 17% H.
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