Question

A compound contains 87.4 % nitrogen 12.6% hydrogen. If the molecular mass of the compound is 32.05u, what is its molecular formula?

Answer 1

hey mate
here's the solution

Answer 2

Answer: 2N2H4

Explanation:

N= 87.4%

H= 12.6%

Atomic mass

N=14

H= 1

N= 87.4/14

N= 6.25

H= 12.6/1

H= 12.6

H is twice the N

NH2 = 2(NH2)= N2H4

Write the symbols that have a positive charge valency first.

The valency of each atom should then be written on top of its symbol.

Divide the valency number by their highest common factor, ignoring the positive or negative radicle, in the third step.

The radicle's valency should be switched.

Last but not least, jot down the alternate valency number to the right of the radicle.

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