Question

A compound forms fcc structures. What is the number
of octahedral voids formed in 0.3 mol of it ?​

Answer 1

Answer:

Number of atoms in close packaging = 0.5 mol

1 has 6.022×10

23

particles

So that

Number of close-packed particles

=0.5×6.022×10

23

=3.011×10

23

Number of tetrahedral voids = 2 × number of atoms in close packaging

Plug the values we get

Number of tetrahedral voids =2×3.011×10

23

=6.022×10

23

Number of octahedral voids = number of atoms in close packaging

So that

Number of octahedral voids =3.011×10

23

Total number of voids = Tetrahedral void + octahedral void

=6.022×10

23

+3.011×10

23

=9.03×10

23

Answer 2

Answer:

Explanation:

Concept:

The concept of organic chemistry will be used to solve this question.

Given:

The compound was formed in fcc structures.The number of atoms in the fcc structure is $0.3 mol$ .

To Find:

We have to find the number of octahedral voids in $0.3 mol$ of fcc structure.

Solution:

The number of atoms in the compound is $0.3 mol$.

The number of partcicle of $1$ mole is $6.022 \times 10^{23}$ .

Then the number of particles in this amount of compound is $6.022 \times 10^{23} \times 0.3=1.8066 \times 10^{23}$ atoms.

The number of octahedral voids is equals to the number of atoms in the compound.

Then the number of octahedral voids is $1.8066 \times 10^{23}$ in the $0.3 mol$ of compound.

So the correct answer is $1.8066 \times 10^{23}$.

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