Question

A compound forms HCP structure what is the number. Of octahedral voids telrahedral voids total voids formed in 0.4 mol of it

Answer 1

Answer:

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Explanation:

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Solution :

Number of atoms in 0.4 mol = 0.4 × NA

= 0.4 × 6.022 × 1023 = 2.4098 × 1023

(a) Number of octahedral voids = number

of atoms = 2.4098 × 1023

(b) Number of tetrahedral voids

= 2×number of atoms

= 2×2.4098×1023

= 4.818×1023

(c) Total number of voids

= 2.409×1023+ 4.818×1023

= 7.227 × 1023