Question

A compound forms hcp structure. What is the number of (a) octahedral voids (b) tetrahedral voids (c) total voids formed in 0.4 mol of it.​

Answer 1

$\huge\star\mathfrak\blue{{Answer:-}}$

Solution :

Number of atoms in 0.4 mol = 0.4 × NA

= 0.4 × 6.022 × 1023 = 2.4098 × 1023

(a) Number of octahedral voids = number

of atoms = 2.4098 × 1023

(b) Number of tetrahedral voids

= 2×number of atoms

= 2×2.4098×1023

= 4.818×1023

(c) Total number of voids

= 2.409×1023+ 4.818×1023

= 7.227 × 1023