A compound forms hcp structure. What is the number of (a) octahedral voids (b) tetrahedral voids (c) total voids formed in 0.4 mol of it.
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Solution :
Number of atoms in 0.4 mol = 0.4 × NA
= 0.4 × 6.022 × 1023 = 2.4098 × 1023
(a) Number of octahedral voids = number
of atoms = 2.4098 × 1023
(b) Number of tetrahedral voids
= 2×number of atoms
= 2×2.4098×1023
= 4.818×1023
(c) Total number of voids
= 2.409×1023+ 4.818×1023
= 7.227 × 1023
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