A compound forms hcp
structure. What is the number of (a) octahedral voids (b) tetrahedral voids (c) total voids formed in 0.4 mol of it.
Answers
Solution :
Number of atoms in 0.4 mol = 0.4 × NA
= 0.4 × 6.022 × 1023 = 2.4098 × 1023
(a) Number of octahedral voids = number
of atoms = 2.4098 × 1023
(b) Number of tetrahedral voids
= 2×number of atoms
= 2×2.4098×1023
= 4.818×1023
(c) Total number of voids
= 2.409×1023+ 4.818×1023
= 7.227 × 1023
Answer:
(a) octahedral voids = 2.41 × 10²³
(b) tetrahedral voids = 4.82 × 10²³
(c) total voids = 7.23 × 10²³
Explanation:
- In the close packing of spheres, certain hollows left vacant, these holes in the crystal s is called interstitial voids.
- There are two types of voids : octahedral voids and tetrahedral voids. Therefore, the total number of voids is equal to sum of octahedral voids and tetrahedral voids.
- Number of octahedral voids is equal to number of atoms (lattice points) present in the crystal.
- Number of tetrahedral voids is equal to twice of number of number of atoms.
We have given 0.4 moles of compound.
We know that number of atoms in 1 mole = 6.023×10²³ atoms
Then number of atoms in 0.4 moles = 0.4×6.023×10²³
= 2.41 × 10²³ atoms
(a) Number of octahedral voids = Number of atoms in 0.4mol of compound
Number of octahedral voids = 2.41 × 10²³
(b) Number of tetrahedral voids = 2× Number of atoms in 0.4mol crystal
= 2× 2.41 × 10²³
= 4.82 × 10²³
(c) Total number of voids = octahedral voids + tetrahedral voids
Total voids = 2.41 × 10²³ + 4.82 × 10²³
Total voids = 7.23 × 10²³ Voids.