Question

A compound forms hexagonal close packed structure . What is the total no of voids in 0.5 mol of it? How many of these are tetrahedral voids?

Answer 1

Number of close-packed particles = 0.5×6.022×1023= 3.011×1023

Therefore, number of octahedral voids = 3.011×1023

And, number of tetrahedral voids = 2×3.011×1023= 6.022×1023

Therefore, total number of voids = 3.011×1023+ 6.022×1023= 9.033×1023

Answer 2

Good afternoon dear......

Number of close packed particles = 0.5 x 6.022 x 1023= 3.011 x 1023
I.e. number of octahedral voids = 3.011 x 1023.
the number of tetrahedral voids = 2 x 3.011 x 1023= 6.022 x 1023
thn total number of voids = 3.011 x 1023+6.022 x 1023= 9.033 x 1023.

I hope it's helps u alot.


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