Question

a compound has 50%sulphur and 50% oxygen by mass. what will be its empirical formula

Answer 1

☆☆ AS-SALAMU-ALYKUM☆☆

●●●●●●●●●●●●●●●●●●●●

MOLES OF SULPHUR = %OF SULPHUR ÷ ATOMIC MASS OF SULPHUR

MOLES OF SULPHUR = 50 ÷32

MOLES OF SULPHUR =1.56 mol

MOLES OF OXYGEN =%OF OXYGEN ÷ ATOMIC MASS OF OXYGEN

MOLES OF OXYGEN = 50÷16

MOLES OF OXYGEN = 3.12 mol

SIMPLEST RATIO :-

S : O

1.56 : 3.12

SIMPLEST RATIO IS FOUND OUT BY DIVIDING THE NUMBER OF MOLES OF EACH ELEMENT BY SMALLEST NUMBER OF MOLES .

SO

1.56÷1.56 : 3.12÷1.56

1 : 2

IT MEANS S IS 1 WHILE O ARE 2 THAT IS SO2

SO EMPIRICAL FORMULA IS SO2

●●●●●●●●●●●●●●●●●●●●●

♡♤♡INSHALLAH IT WILL HELP U ♡♤♡

●●●●●●●●●●●●●●●●●●●●●

HAVE A NICE DAY☺☺☺☺