Question

) A compound has C= 75.92%, H=6.32% and N= 17.76%.( At mass of C=12, H=1,N=14). Write its Empirical formula.​

Answer 1

Answer:

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Explanation:

EMPIRICAL FORMULA : C5H5N

ELEMENT               %                              

  C                          75.92                  =5

    H                         6.32                    =5

    N                          17.76                  =1

Answer 2

Answer:

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