A compound has the formula PtCl4⋅2KCl...?
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Answer:
The complex is likely potassium hexachloroplatinate, i.e. K2[PtCl6]
Explanation:
Because no precipitate is observed with Ag+, there is no free halide ion present, and so all the halides are bound to platinum metal. And thus K2[PtCl6], a platinum IV+species, is likely. In solution it would give 3 equiv of ions: 2×K++[PtCl6]2−, which is consistent with the conductance measurements.
What is the likely structure of the platinum complex
The complex is likely potassium hexachloroplatinate, i.e. K2[PtCl6]
Explanation:
Because no precipitate is observed with Ag+, there is no free halide ion present, and so all the halides are bound to platinum metal. And thus K2[PtCl6], a platinum IV+species, is likely. In solution it would give 3 equiv of ions: 2×K++[PtCl6]2−, which is consistent with the conductance measurements.
What is the likely structure of the platinum complex
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