Question

A compound have carbon, hydrogen and oxygen in 3:3:1 atomic ratio. If the number of moles in 1 g of the
compound id 6.06 x 10^-3 the molecular formula is the compound will be
(A) C3H3O
(B) C6H6O2
(C) C9H9O3
(D) C12H12O4​

Answer 1

Hi there,

Given :

● Molar ratio is C:H:O= 3:3:1

● C Atomic mass = 12

● O atomic mass = 16

● H atomic mass = 1

● Empirical formula is C3H3O

♧ Molar mass of empirical formula is

12×3+3+16 = 55 gm

♧ Molar mass of the molecular formula can calculated by divide sample mass over number of moles

◇ Mwt = ms÷ n = 1÷6.06*10^-3 = 165 g/mol

♤ So, the number of coefficient

Molar mass of molecular formula divide over molar mass of empirical formula ,

◇ 165÷ 55 = 3

So,

♧ The molecular formula is

《C9H9O3》

♡ Hope the answer is helpful

♡ Plz mark it as brainliest answer