a compound having 4.07% hydrogen , 24.27% carbon and 71.65% chlorine its molecular weight 98.96 what r its empirical formula and molecular formula
Answers
Answer:
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Explanation:
a compound, 4.07g of hydrogen, 24.27g of carbon and 71.65g of chlorine are present. ... Molar mass/ empirical formula = 98.96g/ 49g = 2=n Therefore, Empirical formula = CH2Cl n=2 Hence, molecular formula= C2H4Cl2
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Answer:
Empirical formula --> CH2Cl
Molecular formula --> C2H4Cl2
read the end when you have time :)
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EXPLANATION :
no.of moles of H = 4.07/1 = 4.07
no of moles of C = 24.27/12 = 2.02
" " Cl = 71.65/35.5 = 2.018 ≈ 2.02
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finding simplest ratio and E.F
H = 4.07/2.02 = 2.0148 ≈ 2.02
C = 2.02/2.02 = 1
Cl = 2.02/2.02 = 1
2:1:1
herefore, E.F = H2CCl or CH2Cl
and E.F mass = 12 + 2(1) + 35.5 = 49.5
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finding molecular formula
M.F = E.F × n
we have to find n.
M.F mass = E.F mass × n
n = M.F mass/E.F mass = 98.96/49.5
n = 1.99 ≈ 2
therefore M.F = 2× E.F
Molecular formula = C2H4Cl2
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