Question

A compound having the empirical formula
C3H40 has a molar mass of 168. The molecular
formula of this compound is -
a) C3H4O
b) C6H8O2
c) C6H12O3
d) C9H12O3​

Answer 1

Answer:

C

Explanation:

Molecular formula weight = 168

Empirical formula = C3H4O

Empiricial formula weight = 3×12+4×1+1×16 =58

Molecular formula weight = n× empirical formula weight

n = Mf / Ef

= 168/58

=2.89 ~ 3

n=3

Mf = n×Ef

= (C3H4O)3

= C6H12O3