A compound is formed by two elements m and n. The element nforms ccp and atoms of m occupy 1/3rd of tetrahedral voids. Whatis the formula of the compo
Answers
Since element M are in ccp arrangement, the number of M per unit cell=4The number of tetrahedral void=8But only 1/3rd is occupied by N, therefore 8×1/3rd Hence the formula of the compound is M4N8/3=M12N8or M3N2
hope it helps
please mark this as brainliest
◆ ▬▬▬▬▬▬▬▬▬▬▬▬ ◆
A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids. What is the formula of the compound?
◆ ▬▬▬▬▬▬▬▬▬▬▬▬ ◆
Let the number of atoms of the element N = n
Number of tetravalent voids = 2n
It is given that the atoms of element M occupy 1/3 of the tetrahedral voids.
So that the number of atoms of M = (1/3) × 2n
Ratio of the number of atoms of M and N
M:N =2n/3:n
Multiplying the 3 and divide by n we get
M:N = 2:3
Hence, the formula of the compound is M2N3 .
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬