Question

A compound is found to contain 31.42% sulpher ,31.35 %oxygen and 37.23 %flourine by weight.what is its empirical formula?the molecular weight for this conpound is 102.2g/mol.what is its molecular formula?​

Answer 1

Answer:

Answer is SO(2)F(2)

Explanation:

Let the total mass of compound be 100 gram.

Now sulphur amount will be 31.42gm

oxygen amount will be 31.35 gm

fluorine amount will be 37.23 gm.

Now,

number of moles of sulpher will be 31.42/32 that will be equal to 0.9817

number of moles of oxygen will be 31.35/16 that will be equal to 1.9593

number of moles of fluorine will be 37.23/19 that will be equal to 1.9594

therefore the lowest moles are of sulphur. hence dividing by 0.9817

thus the empirical formula becomes SO(2)F(2)

empirical mass 102 approx.

hence the molecular mass is equal to empirical mass

Thus the molecular formula will be equal to empirical formula.

THUS answer is SO(2)F(2)