a compound lens is made if two lenses having power +15.5D and -5.5D. an object 3cm of height is placed at a distance of 30cm. from this compound lens find out the size of the image
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Answer:
Here, The size of the image is 3.09cm.
Explanation:
Here, As per our given question,
=Total power of the compound lens=15.5D+(-5.5D)
=15.5-5.5
=15D is the Total power.
Now,We have to find out focal length(f)=
=P=1/f
=15=1/f
=15f=1
=f=1/15
=f=0.67 cm
Now, Distance of the image from the mirror,
=1/V-1/U=1/f (Where, U=distance of the object)
=1/V=1/f+1/U
=1/V=1/0.67+1/30
Now, by doing reciprocal in it, we get,
=V=0.67+30
=V=30.67 cm
Now, As it is considered that,
(Magnification)M=V/U,
=M=30.67/30
=M=1.03
Now, height of image=M=hi/ho (Where, hi=height of image, ho=height of object)
=1.03=hi/3
=hi=1.03×3
=hi=3.09 cm (Answer).
Thank you.
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