A compound lens is made of a convex lens of power 10D and a concave lens of power 5D. An object 2 cm high is placed in front of this combination at a distance 40 cm from it. Find nature and size of the images formed.
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focal length is =
1/5=100/5=20cm
now,h(o)=2cm
u=-40cm
1/v-1/u=1/f
=1/v=1/f+1/u
=1/v=1/20-1/40
=1/v=2-1/40
=1/v=1/40
=v=40cm
m=h(i)/h(o)=v/u
=h(i)=40/-40×2=-2=h(i)
h(i)/h(o)=-1
the image is formed at 40cm from the lens and is real inverted and is the same size as that of the object.
1/5=100/5=20cm
now,h(o)=2cm
u=-40cm
1/v-1/u=1/f
=1/v=1/f+1/u
=1/v=1/20-1/40
=1/v=2-1/40
=1/v=1/40
=v=40cm
m=h(i)/h(o)=v/u
=h(i)=40/-40×2=-2=h(i)
h(i)/h(o)=-1
the image is formed at 40cm from the lens and is real inverted and is the same size as that of the object.
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size will be 2 cm.. and nature will be same size of obj. real and inverted
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