Question

A compound microscope has objective lens and eye−piece of focal lengths 5cm and 8 cm respectively. If an object is placed at a distance of 8 cm from the objective, then find the magnification produced by the microscope when the final image at near point

Answer 1

Explanation:

Given, u0=3cm,f0=2.5cm,v0=image distance for objective lens

f01=v01−u01

v01=f01+u01=2.51−31

v0=3−2.53×2.5=15cm

Object distance for eye piece =20−15=5cm

Given, ue=−5cm,fe=6cm,ve=image formed by eye piece

ve1=fe1