Question

A compound microscope with an objective of 10 cm focal length and an eyepiece of 2cm

Answer 1

Answer:

Explanation:

Focal length of objective fo = 1cm

Focal length of eyepiece fe = 2cm

Distance of distinct vision D=25 cm

Tube length L = 20cm

To find-

Magnifying power of microscope M=?

Solution-

Magnifying by microscope is given by

M = mo×me

M = D×L/fo×fe

M = 20×25/1×2

M = 250

Magnification is 250 when image is formed near eye.

Hope that was helpful...