Question

A compound of aluminium and chlorine is composed of 9 g Al for every 35.5 g of chlorinr the empirical formula of compound is

Answer 1

Answer:

mole of Al= 9÷27=0.33=. 0.33÷0.33=1

mole of cl=1=. 1÷0.3=3.0

The empirical formula will be Alcl3