Question

a compound of carbon ,hydrogen and nitrogen contains these elements in the ratio 9:1:3.5 caluclate emprical formula .if vapour density is 58 then find molecular formula

Answer 1

Answer:

The empirical formula =C3H4N Empirical formula mass=(3×12)+(4×1)+14=54 n = Mol.Mass/Emp.mass =58/54 =29/27 Thus,molecular formula of the compound =29/27×Empirical formula ⇒29/27×C3H4N ⇒C9H8N27