. A compound of carbon, hydrogen and nitrogen contains three elements in the ratio 9: 1:3-5. Calculate molecular formula of the compound (Vapour density of the compound is 54).
Answers
Answered by
0
Correct option is
A
x=6,y=8,z=2
In a certain compound, the ratio of C:H:N=9:1:3.5
Molar ratio of C:H:N =
12
9
:
1
1
:
14
3.5
=0.75:1:10.25
Integer ratio =
0.25
0.75
:
0.25
1
:
0.25
0.25
=3:4:1
Therefore, the empirical formula is C
3
H
4
N.
Empirical weight =12×3+1×4+14=54 g.
Given the molecular weight is 108 g.
n=
EFw
Mw
=
54
108
=2
Molecular formula =C
6
H
8
N
2
Similar questions