A compound of carbon, hydrogen, and oxygen is found to contain 40% of carbon, 6.7% of hydrogen
and 53.3% of oxygen. Calculate its empirical formula. If its vapour density is 30, calculate the molecular
formula.
Answers
Answer:
Explanation:
Elements Atomic weights Percentage Ratio no.of moles
carbon 12 40 40/12=3.33 3.33/3.33 =1 hydrogen 1 6.7 6.7/1 =6.7 6.7/3.33 = 2(aprom)
oxygen 16 53.3 53.3/16=3.33 3.33/3.33=1
empirical formula= C H 2 O
empirical formula weight=12+2+16
= 30
molecular weight = 2×vapour density
= 2×30
=60
molecular formula = empirical formula × n
n= molecular formula weight/empirical formula weight
n= 60/30
n=2
∴molecular formula= C H 2 O × 2
=C 2 H 4 O 2
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Answer: