Question

A compound of contains 20% sulphur the molecular weight of compound is

Answer 1

20g of sulpher is present in 100g
then,32g of sulpher is presnt in 160g
so,mass of sulpher in the compound is 160g.
Now, most of the oxides with sulpher gives the ratio of 1:3(ratio of molecules)
So, if mass of sulpher is 160g mass of oxygen is 160x3=480g
therefore,mass of the compound 160+480g=640g.


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Answer 2

Answer:

The minimum molecular weight $=160 \mathrm{~g} / \mathrm{mole}$.

Explanation:

$20g$ of sulfur exists present in $100g$

then,$32g$ of sulfur exists present in $160g$

so, the mass of sulfur in the compound is $160g.$

Now, most of the oxides with sulfur show the ratio of $1:3$ (ratio of molecules)

So, if the mass of sulfur exists $160g.$ mass of oxygen exists

$160*3=480g$

$x=$ minimum molecular weight

$&x=\frac{32}{20} \times 100$

$&=160 \mathrm{~g} / \text { mole }$

Therefore, the minimum molecular weight $=160 \mathrm{~g} / \mathrm{mole}$.

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