Question

A compound of formula a2b3 has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms:

Answer 1

Answer:

Explanation:

Let us suppose that B will produce hcp lattice  

Total number of atoms in  B = 6

Tetrahedral void occupied=  2N

Therefore N= 6

Tetrahedral void = 2*6 = 12

Now number of atoms in  A = 1/3 x Tertahedral void

                                              = 1/3 * 12 = 4

A4B6 (Multiple of 2)

Therefore answer is:  A2B3