A compound of molecular formula c8h8o2 reacts with acetophenone to form a single cross-aldol product in the presence of base. The same compound on reaction with conc. Naoh forms benzyl alcohol as one of the products. The structure of the compound is :
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hence proved it's true answer
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Hey dear,
● Answer -
Name of the compound is 4-Anisaldehyde (p-methoxybenzaldehyde).
[Refer to image for structure of compound.]
● Explanation -
4-anisaldehyde reacts with acetophenone to form 4-methoxychalcone.
C8H8O2 + C8H8O --> C16H14O2 + H2O
4-anisaldehyde on reaction with sodium hydroxide gives benzyl alcohol & sodium methanoate.
C8H8O2 + NaOH --> C7H8O + HCONa
Thanks for asking..
● Answer -
Name of the compound is 4-Anisaldehyde (p-methoxybenzaldehyde).
[Refer to image for structure of compound.]
● Explanation -
4-anisaldehyde reacts with acetophenone to form 4-methoxychalcone.
C8H8O2 + C8H8O --> C16H14O2 + H2O
4-anisaldehyde on reaction with sodium hydroxide gives benzyl alcohol & sodium methanoate.
C8H8O2 + NaOH --> C7H8O + HCONa
Thanks for asking..
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