Question

A compound on analysis found to contain 55% of C , 9% of H and 36% of oxygen it's molar mass is 88. calculate the formula of the compound​

Answer 1

Answer:

compound on analysis found to contain 55% of C , 9% of H and 36% of oxygen it's molar mass is 88. calculate the formula of the compound

Explanation:

compound on analysis found to contain 55% of C , 9% of H and 36% of oxygen it's molar mass is 88. calculate the formula of the compoundcompound on analysis found to contain 55% of C , 9% of H and 36% of oxygen it's molar mass is 88. calculate the formula of the compoundcompound on analysis found to contain 55% of C , 9% of H and 36% of oxygen it's molar mass is 88. calculate the formula of the compoundcompound on analysis found to contain 55% of C , 9% of H and 36% of oxygen it's molar mass is 88. calculate the formula of the compoundcompound on analysis found to contain 55% of C , 9% of H and 36% of oxygen it's molar mass is 88. calculate the formula of the compound

Answer 2

Answer:

your answer is.........

Explanation:

Let amount of organic = 100 gm

amount of carbon = 54.55 g

amount of hydrogen = 9.09 g

Amount of oxygen = 36.26 g

number of mole of carbon = 1234.55

                                            =4.54583

number of mole of hydrogen = 1.0189.09

                                                    =9

number of mole of oxygen = 1636.26

                                                =2.26

4.54833:9:2.26

2:4:1

organic compounds Empirical formula

  =C2H4O

Molecular weight = 24+4+16=44 

(for empirical)

Molecular weight = 2× vapour density 

                            =2×44=88 g

To molecular formula be = C4H8O2